English

$\omega$-Lyndon words

Combinatorics 2019-07-10 v2

Abstract

Let \A\A be a finite non-empty set and \preceq a total order on \A\nats\A^\nats verifying the following lexicographic like condition: For each n\natsn\in \nats and u,v\An,u, v\in \A^n, if uωvωu^\omega \prec v^\omega then uxvyux\prec vy for all x,y\A\nats.x, y \in \A^\nats. A word x\A\natsx\in \A^\nats is called ω\omega-Lyndon if xyx\prec y for each proper suffix yy of x.x. A finite word w\A+w\in \A^+ is called ω\omega-Lyndon if wωvωw^\omega \prec v^\omega for each proper suffix vv of w.w. In this note we prove that every infinite word may be written uniquely as a non-increasing product of ω\omega-Lyndon words.

Keywords

Cite

@article{arxiv.1907.01072,
  title  = {$\omega$-Lyndon words},
  author = {Mickaël Postic and Luca Q. Zamboni},
  journal= {arXiv preprint arXiv:1907.01072},
  year   = {2019}
}
R2 v1 2026-06-23T10:09:22.236Z