Normal functionals on Lipschitz spaces are weak$^\ast$ continuous
Functional Analysis
2023-02-28 v2
Abstract
Let be the space of Lipschitz functions on a complete metric space that vanish at a base point. We show that every normal functional in is weak continuous, answering a question by N. Weaver.
Keywords
Cite
@article{arxiv.2004.14310,
title = {Normal functionals on Lipschitz spaces are weak$^\ast$ continuous},
author = {Ramón J. Aliaga and Eva Pernecká},
journal= {arXiv preprint arXiv:2004.14310},
year = {2023}
}
Comments
v2: Revised version