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Normal functionals on Lipschitz spaces are weak$^\ast$ continuous

Functional Analysis 2023-02-28 v2

Abstract

Let Lip0(M)\operatorname{Lip}_0(M) be the space of Lipschitz functions on a complete metric space MM that vanish at a base point. We show that every normal functional in Lip0(M)\operatorname{Lip}_0(M)^\ast is weak^* continuous, answering a question by N. Weaver.

Keywords

Cite

@article{arxiv.2004.14310,
  title  = {Normal functionals on Lipschitz spaces are weak$^\ast$ continuous},
  author = {Ramón J. Aliaga and Eva Pernecká},
  journal= {arXiv preprint arXiv:2004.14310},
  year   = {2023}
}

Comments

v2: Revised version

R2 v1 2026-06-23T15:11:25.525Z