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Negative-energy PT-symmetric Hamiltonians

High Energy Physics - Theory 2014-08-28 v1 Mathematical Physics math.MP Quantum Physics

Abstract

The non-Hermitian PT-symmetric quantum-mechanical Hamiltonian H=p2+x2(ix)ϵH=p^2+x^2(ix)^\epsilon has real, positive, and discrete eigenvalues for all ϵ0\epsilon\geq 0. These eigenvalues are analytic continuations of the harmonic-oscillator eigenvalues En=2n+1E_n=2n+1 (n=0, 1, 2, 3, ...) at ϵ=0\epsilon=0. However, the harmonic oscillator also has negative eigenvalues En=2n1E_n=-2n-1 (n=0, 1, 2, 3, ...), and one may ask whether it is equally possible to continue analytically from these eigenvalues. It is shown in this paper that for appropriate PT-symmetric boundary conditions the Hamiltonian H=p2+x2(ix)ϵH=p^2+x^2(ix)^\epsilon also has real and {\it negative} discrete eigenvalues. The negative eigenvalues fall into classes labeled by the integer N (N=1, 2, 3, ...). For the Nth class of eigenvalues, ϵ\epsilon lies in the range (4N6)/3<ϵ<4N2(4N-6)/3<\epsilon<4N-2. At the low and high ends of this range, the eigenvalues are all infinite. At the special intermediate value ϵ=2N2\epsilon=2N-2 the eigenvalues are the negatives of those of the conventional Hermitian Hamiltonian H=p2+x2NH=p^2+x^{2N}. However, when ϵ2N2\epsilon\neq 2N-2, there are infinitely many complex eigenvalues. Thus, while the positive-spectrum sector of the Hamiltonian H=p2+x2(ix)ϵH=p^2+x^2(ix)^\epsilon has an unbroken PT symmetry (the eigenvalues are all real), the negative-spectrum sector of H=p2+x2(ix)ϵH=p^2+x^2(ix)^\epsilon has a broken PT symmetry (only some of the eigenvalues are real).

Keywords

Cite

@article{arxiv.1203.6590,
  title  = {Negative-energy PT-symmetric Hamiltonians},
  author = {Carl M. Bender and Daniel W. Hook and S. P. Klevansky},
  journal= {arXiv preprint arXiv:1203.6590},
  year   = {2014}
}

Comments

12 pages, 8 figures

R2 v1 2026-06-21T20:41:59.021Z