English

$\mathbb{S}^6$ (or any of $\mathbb{S}^2 \times \mathbb{S}^4$, $\mathbb{S}^2\times\mathbb{S}^6$, or $\mathbb{S}^6\times \mathbb{S}^6$, respectively) is not diffeomorphic to a complex manifold

Differential Geometry 2024-05-28 v2

Abstract

We identify all metrics on a closed nn-manifold with their Nash isometric embeddings into a standard sphere of large, but fixed dimension, and use the Palais' isotopic extension theorem to identify their deformations with the isotopic deformations of their embeddings, the deformations of metrics in a conformal class identified with their corresponding isotopic conformal deformations. If n3n\geq 3, we characterize metrics of constant scalar curvature in terms of properties of extrinsic quantities of their associated embeddings, and prove that any metric on the manifold of constant positive scalar curvature, which can be minimally embedded into this background sphere, is a Yamabe metric in its conformal class. We then use Simons' gap theorem to study the extrinsic quantities of almost complex Hermitian deformations, by Yamabe metrics, of the standard minimal almost complex isometric embeddings of \mbS6\mb{S}^6, \mbS2×\mbS4\mb{S}^2 \times \mb{S}^4, \mbS2×\mbS6\mb{S}^2\times\mb{S}^6, and \mbS6×\mbS6\mb{S}^6\times \mb{S}^6, respectively, and prove that none of these manifolds carry integrable almost complex structures. :

Keywords

Cite

@article{arxiv.2204.12628,
  title  = {$\mathbb{S}^6$ (or any of $\mathbb{S}^2 \times \mathbb{S}^4$, $\mathbb{S}^2\times\mathbb{S}^6$, or $\mathbb{S}^6\times \mathbb{S}^6$, respectively) is not diffeomorphic to a complex manifold},
  author = {Santiago R Simanca},
  journal= {arXiv preprint arXiv:2204.12628},
  year   = {2024}
}

Comments

Edite to improve clarity of exposition, statements and proofs, and to eliminate a number of misprints/typos