Magnetic spiral order in the square-lattice spin system (CuBr)Sr$_{2}$Nb$_{3}$O$_{10}$

A. V. Mikheyenkov; V. E. Valiulin; A. F. Barabanov

doi:10.1016/j.physb.2020.412533

Magnetic spiral order in the square-lattice spin system (CuBr)Sr$_{2}$Nb$_{3}$O$_{10}$

Materials Science 2020-10-28 v1 Strongly Correlated Electrons

Authors: A. V. Mikheyenkov , V. E. Valiulin , A. F. Barabanov

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Abstract

We address quantum spin helical states in the strongly frustrated Heisenberg model. Contrary to conventional Dzyaloshinskii-Moriya approach we show that such states appear without central symmetry breaking. As an example, we demonstrate that the magnetic and thermodynamic properties of the quasi-two-dimensional square-lattice compound $\mathrm{(CuBr)Sr_{2}Nb_{3}O_{10}}$ can be interpreted within 2D $S = 1/2$ $J_1-J_2-J_3$ Heisenberg model. In this compound neutron experiment indicates helical spin order while central symmetry does hold.

Keywords

magnetic spiral order square-lattice spin system heisenberg model frustration central symmetry neutron experiment quantum spin states

Cite

@article{arxiv.1912.06399,
  title  = {Magnetic spiral order in the square-lattice spin system (CuBr)Sr$_{2}$Nb$_{3}$O$_{10}$},
  author = {A. V. Mikheyenkov and V. E. Valiulin and A. F. Barabanov},
  journal= {arXiv preprint arXiv:1912.06399},
  year   = {2020}
}

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