Lipschitz equivalence of subsets of self-conformal sets
Metric Geometry
2015-05-14 v1
Abstract
We give sufficient conditions to guarantee that if two self-conformal sets E and F have Lipschitz equivalent subsets of positive measure, then there is a bilipschitz map of E into, or onto, F.
Keywords
Cite
@article{arxiv.0909.1928,
title = {Lipschitz equivalence of subsets of self-conformal sets},
author = {Marta Llorente and Pertti Mattila},
journal= {arXiv preprint arXiv:0909.1928},
year = {2015}
}