English

Improved Moser--Trudinger inequality for functions with mean value zero in $\mathbb R^n$ and its extremal functions

Functional Analysis 2017-08-11 v1 Analysis of PDEs

Abstract

Let Ω\Omega be a bounded smooth domain in Rn\mathbb R^n, W1,n(Ω)W^{1,n}(\Omega) be the Sobolev space on Ω\Omega, and λ(Ω)=inf{unn:Ωudx=0,un=1}\lambda(\Omega) = \inf\{\|\nabla u\|_n^n: \int_\Omega u dx =0, \|u\|_n =1\} be the first nonzero Neumann eigenvalue of the nn-Laplace operator Δn-\Delta_n on Ω\Omega. For 0α<λ(Ω)0 \leq \alpha < \lambda(\Omega), let us define u1,αn=unnαunn\|u\|_{1,\alpha}^n =\|\nabla u\|_n^n -\alpha \|u\|_n^n. We prove, in this paper, the following improved Moser--Trudinger inequality on functions with mean value zero on Ω\Omega, supuW1,n(Ω),Ωudx=0,u1,α=1Ωeβnunn1dx<, \sup_{u\in W^{1,n}(\Omega), \int_\Omega u dx =0, \|u\|_{1,\alpha} =1} \int_{\Omega} e^{\beta_n |u|^{\frac n{n-1}}} dx < \infty, where βn=n(ωn1/2)1/(n1)\beta_n = n (\omega_{n-1}/2)^{1/(n-1)}, and ωn1\omega_{n-1} denotes the surface area of unit sphere in Rn\mathbb R^n. We also show that this supremum is attained by some function uW1,n(Ω)u^*\in W^{1,n}(\Omega) such that Ωudx=0\int_\Omega u^* dx =0 and u1,α=1\|u^*\|_{1,\alpha} =1. This generalizes a result of Ngo and Nguyen \cite{NN17} in dimension two and a result of Yang \cite{Yang07} for α=0\alpha=0, and improves a result of Cianchi \cite{Cianchi05}.

Keywords

Cite

@article{arxiv.1708.03028,
  title  = {Improved Moser--Trudinger inequality for functions with mean value zero in $\mathbb R^n$ and its extremal functions},
  author = {Van Hoang Nguyen},
  journal= {arXiv preprint arXiv:1708.03028},
  year   = {2017}
}

Comments

24 pages, to appear in Nonlinear Analysis