English

If $R^m \cong R^n$ must $m=n$?

Rings and Algebras 2022-03-25 v1

Abstract

A fundamental theorem of linear algebra asserts that every basis for the vector space Rn\mathbb{R}^n has nn elements. In this expository note we present a theorem of W. G. Leavitt describing one way in which this invariant basis number property can fail when one does linear algebra over rings, rather than over fields. We give a proof of Leavitt's theorem that combines ideas of P. M. Cohn and A. L. S. Corner into an elementary form requiring only a nodding acquaintance with matrices and modular arithmetic.

Keywords

Cite

@article{arxiv.2203.13155,
  title  = {If $R^m \cong R^n$ must $m=n$?},
  author = {Tyrone Crisp},
  journal= {arXiv preprint arXiv:2203.13155},
  year   = {2022}
}

Comments

7 pages, expository note