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Generalized Hilbert operators on Hardy spaces

Functional Analysis 2026-07-30 v1

Abstract

Let gH(D)g\in H(\mathbb D), the generalized Hilbert operator Hg\mathcal H_g is defined by Hg(f)(z)=01f(t)g(tz)dt,  zD  fH(D). \mathcal H_g(f)(z)=\int_0^1 f(t)g'(tz)dt,\ \ z\in \mathbb D\, \ \ f \in H(\mathbb D). Let Rp=H(Hp)\mathcal R_p=\mathcal H(H^p) be the range of the classical Hilbert operator on Hardy space, equipped with the pullback norm, and let (Rp,Hp)(\mathcal R_p,H^p) denote the Hadamard multiplier space. For 1<p<1<p<\infty, we prove the exact multiplier characterization Hg:HpHp  is boundedg(Rp,Hp), \mathcal H_g:H^{p}\longrightarrow H^{p} \ \ \text{is bounded} \quad\Longleftrightarrow\quad g'\in(\mathcal R_p,H^p), and an equivalent Hilbert-matrix bilinear criterion Bp(g)<\mathfrak B_p(g)<\infty. We identify the multiplier space completely when 1<p21<p\le2: (Rp,Hp)=H(p,,1p). (\mathcal R_p,H^p)=H\left(p,\infty,\frac1{p'}\right). For p>2p>2, we prove that the multiplier space (Rp,Hp)(\mathcal R_p,H^p) is strictly contained in H(p,,1p)H\left(p,\infty,\frac1{p'}\right). This shows that gΛ(p,1/p)g\in \Lambda(p,1/p) does not imply that Hg\mathcal H_g is bounded on HpH^p, giving a negative answer to the conjecture posed by Galanopoulos, Girela, Pel\'aez and Siskakis. In addition, we locate two previously known sufficient classes inside the multiplier space. This allow us obtain a complete coefficient characterization of Hg\mathcal H_g on HpH^{p} for gH(D)g \in H(\mathbb D) with nonnegative decreasing Taylor coefficients. We then study the structure of (Rp,Hp)(\mathcal R_p,H^p). % It turns out that (Rp,Hp)(\mathcal{R}_p,H^p) contains all polynomials as well as Cauchy transforms. We show that the multiplier spaces (Rp,Hp)(\mathcal{R}_p,H^p) form a strictly increasing family with respect to the exponent pp.

Cite

@article{arxiv.2607.28221,
  title  = {Generalized Hilbert operators on Hardy spaces},
  author = {Yuting Guo and Pengcheng Tang},
  journal= {arXiv preprint arXiv:2607.28221},
  year   = {2026}
}