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Gaussians never extremize Strichartz inequalities for hyperbolic paraboloids

Classical Analysis and ODEs 2019-11-28 v1 Analysis of PDEs

Abstract

For ξ=(ξ1,ξ2,,ξd)Rd\xi = (\xi_1, \xi_2, \ldots, \xi_d) \in \mathbb{R}^d let Q(ξ):=j=1dσjξj2Q(\xi) := \sum_{j=1}^d \sigma_j \xi_j^2 be a quadratic form with signs σj{±1}\sigma_j \in \{\pm1\} not all equal. Let SRd+1S \subset \mathbb{R}^{d+1} be the hyperbolic paraboloid given by S={(ξ,τ)Rd×R : τ=Q(ξ)}S = \big\{(\xi, \tau) \in \mathbb{R}^{d}\times \mathbb{R} \ : \ \tau = Q(\xi)\big\}. In this note we prove that Gaussians never extremize an Lp(Rd)Lq(Rd+1)L^p(\mathbb{R}^d) \to L^{q}(\mathbb{R}^{d+1}) Fourier extension inequality associated to this surface.

Keywords

Cite

@article{arxiv.1911.11796,
  title  = {Gaussians never extremize Strichartz inequalities for hyperbolic paraboloids},
  author = {Emanuel Carneiro and Lucas Oliveira and Mateus Sousa},
  journal= {arXiv preprint arXiv:1911.11796},
  year   = {2019}
}

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7 pages