English

Exponents for three-dimensional simultaneous Diophantine approximations

Number Theory 2010-12-09 v2

Abstract

Let Θ=(θ1,θ2,θ3)R3\Theta = (\theta_1,\theta_2,\theta_3)\in \mathbb{R}^3. Suppose that 1,θ1,θ2,θ31,\theta_1,\theta_2,\theta_3 are linearly independent over Z\mathbb{Z}. For Diophantine exponents α(Θ)=sup{γ>0:lim supt+tγψΘ(t)<+}, \alpha(\Theta) = \sup \{\gamma >0:\,\,\, \limsup_{t\to +\infty} t^\gamma \psi_\Theta (t) <+\infty \} , β(Θ)=sup{γ>0:lim inft+tγψΘ(t)<+}\beta(\Theta) = \sup \{\gamma >0:\,\,\, \liminf_{t\to +\infty} t^\gamma \psi_\Theta (t) <+\infty\} we prove β(Θ)1/2(α(Θ)/1α(Θ)+α(Θ)/1α(Θ))2+4α(Θ)/1α(Θ))α(Θ) \beta (\Theta) \ge {1/2} ({\alpha (\Theta)}/{1-\alpha(\Theta)} +\sqrt{{\alpha(\Theta)}/{1-\alpha(\Theta)})^2 +{4\alpha(\Theta)}/{1-\alpha(\Theta)}}) \alpha (\Theta)

Keywords

Cite

@article{arxiv.1009.0987,
  title  = {Exponents for three-dimensional simultaneous Diophantine approximations},
  author = {Nikolay Moshchevitin},
  journal= {arXiv preprint arXiv:1009.0987},
  year   = {2010}
}

Comments

8 pages, correction of misprints, submitted to Czechoslovak Mathematical Journal

R2 v1 2026-06-21T16:09:50.952Z