Explicit factorization of $x^{2^nd}-1$ over a finite field
Combinatorics
2018-07-03 v1
Abstract
Let be a finite field of odd characteristic containing elements and integer . In this paper, the explicit factorization of over is obtained when is an odd divisor of .
Cite
@article{arxiv.1807.00274,
title = {Explicit factorization of $x^{2^nd}-1$ over a finite field},
author = {Manjit Singh},
journal= {arXiv preprint arXiv:1807.00274},
year = {2018}
}