Explanation of the mass of the muon
Abstract
The difference of the rest masses m(pi^+-) - m(mu^+-) is nearly equal to 1/4 of the rest mass of the pi^(+-) mesons and is equal to the sum of the rest masses of the 0.7 times 10^9 muon neutrinos (respectively anti-muon neutrinos) which are in the cubic lattice of the pi^(+-) mesons according to the standing wave model. In the decay of a pi^(+) or pi^(-) meson all muon neutrinos, respectively anti-muon neutrinos, of the cubic lattice of the pi^(+-) mesons are emitted. The sum of the oscillation energies of all neutrinos in the pi^(+-) mesons is the same as the sum of the oscillation energies of the remaining neutrinos in the mu^(+-) mesons. Consequently the mass of the mu^(+-) mesons is equal to m(pi^+-) - 0.7 times 10^9 m(nu_mu) or 0.75 times m(pi^+-), within 1% in agreement with the measured ratio m(mu^+-) / m(pi^+-) = 0.757028.
Cite
@article{arxiv.physics/0110005,
title = {Explanation of the mass of the muon},
author = {E. L. Koschmieder},
journal= {arXiv preprint arXiv:physics/0110005},
year = {2007}
}
Comments
7 pages. See: arXiv hep-lat/0104016, hep-lat/0002016, hep-ph/0002179