Every graph has an embedding in $S^3$ containing no non-hyperbolic knot
Abstract
In contrast with knots, whose properties depend only on their extrinsic topology in , there is a rich interplay between the intrinsic structure of a graph and the extrinsic topology of all embeddings of the graph in . For example, it was shown in [2] that every embedding of the complete graph in contains a non-trivial knot. Later in it was shown that for every , there is a complete graph such that every embedding of in contains a knot whose minimal crossing number is at least . Thus there are arbitrarily complicated knots in every embedding of a sufficiently large complete graph in . We prove here the contrasting result that every graph has an embedding in such that every non-trivial knot in that embedding is hyperbolic. Our theorem implies that every graph has an embedding in which contains no composite or satellite knots.
Keywords
Cite
@article{arxiv.0906.2229,
title = {Every graph has an embedding in $S^3$ containing no non-hyperbolic knot},
author = {Erica Flapan and Hugh Howards},
journal= {arXiv preprint arXiv:0906.2229},
year = {2009}
}
Comments
12 pages 4 figures