Equivalence between pathbreadth and strong pathbreadth
Computational Complexity
2018-09-18 v1 Data Structures and Algorithms
Abstract
We say that a given graph has \emph{pathbreadth} at most , denoted , if there exists a Roberston and Seymour's path decomposition where every bag is contained in the -neighbourhood of some vertex. Similarly, we say that has \emph{strong pathbreadth} at most , denoted , if there exists a Roberston and Seymour's path decomposition where every bag is the complete -neighbourhood of some vertex. It is straightforward that for any graph . Inspired from a close conjecture in [Leitert and Dragan, COCOA'16], we prove in this note that .
Cite
@article{arxiv.1809.06041,
title = {Equivalence between pathbreadth and strong pathbreadth},
author = {Guillaume Ducoffe and Arne Leitert},
journal= {arXiv preprint arXiv:1809.06041},
year = {2018}
}