English

Decomposing with smooth sets

Logic 2016-09-06 v1

Abstract

A subset of Euclidean space will be said to be nn-smooth if it has an nn-dimensional tangent plane at each of its points. Let dn{\frak d}_n denote the least number nn-smooth sets into which n+1n+1-dimensional Euclidean space can be decomposed. For each nn it is shown to be consistent that dn>dn+1{\frak d}_n > {\frak d}_{n+1} . Moreover, the inequalities dn+1+{\frak d}_{n+1}^+ \geq {\frak d}_nareestablishedwhere are established where {\frak d}_1isdefinedtobethecontinuum.Thecardinalinvariant is defined to be the continuum. The cardinal invariant {\frak d}_2isshowntobethesameastheleast is shown to be the same as the least \kappasuchthateachcontinuousfunctionfromtherealstotherealscanbedecomposedinto such that each continuous function from the reals to the reals can be decomposed into \kappa$ differentiable functions.

Keywords

Cite

@article{arxiv.math/9501204,
  title  = {Decomposing with smooth sets},
  author = {Juris Steprāns},
  journal= {arXiv preprint arXiv:math/9501204},
  year   = {2016}
}