Complexity of Inverting the Euler Function
Abstract
We present an algorithm to invert the Euler function . The algorithm, for a given , in polynomial time ``on average'', finds the set of all solutions to . In fact, in the worst case, is exponentially large, and cannot be computed in polynomial time. In the opposite direction, we show, under a widely accepted number theoretic conjecture, that there is a polynomial time reduction of the Partition Problem, an NP-complete problem, to the problem of deciding whether has a solution for a small set of integers n. This shows that the problem of deciding whether a given finite set of integers S contains a totient is NP-complete. A totient is an integer n that lies in the image of the phi function; that is, an integer n for which there exists an integer m solving phi(m) = n. Finally, we establish close links between of inverting the Euler function and the integer factorization problem.
Cite
@article{arxiv.math/0404116,
title = {Complexity of Inverting the Euler Function},
author = {Scott Contini and Ernie Croot and Igor Shparlinski},
journal= {arXiv preprint arXiv:math/0404116},
year = {2007}
}
Comments
Slight restatement of results in introduction and in section 4