English

Bounded cohomology is not a profinite invariant

Group Theory 2024-06-05 v2 Number Theory

Abstract

We construct pairs of residually finite groups with isomorphic profinite completions such that one has non-vanishing and the other has vanishing real second bounded cohomology. The examples are lattices in different higher rank simple Lie groups. Using Galois cohomology, we actually show that SO0(n,2)\operatorname{SO}^0(n,2) for n6n \ge 6 and the exceptional groups E6(14)E_{6(-14)} and E7(25)E_{7(-25)} constitute the complete list of higher rank Lie groups admitting such examples.

Keywords

Cite

@article{arxiv.2305.18904,
  title  = {Bounded cohomology is not a profinite invariant},
  author = {Daniel Echtler and Holger Kammeyer},
  journal= {arXiv preprint arXiv:2305.18904},
  year   = {2024}
}

Comments

Final version to appear in Canad. Math. Bull., 14 pages