English

Betti posets and the Stanley depth

Combinatorics 2016-06-07 v2 Commutative Algebra

Abstract

Let SS be a polynomial ring and let ISI \subseteq S be a monomial ideal. In this short note, we propose the conjecture that the Betti poset of II determines the Stanley projective dimension of S/IS/I or II. Our main result is that this conjecture implies the Stanley conjecture for II, and it also implies that sdepthS/IdepthS/I1. \operatorname{sdepth} S/I \geq \operatorname{depth} S/I - 1. Recently, Duval et al. found a counterexample to the Stanley conjecture, and their counterexample satisfies sdepthS/I=depthS/I1\operatorname{sdepth} S/I = \operatorname{depth} S/I - 1. So if our conjecture is true, then the conclusion is best possible.

Keywords

Cite

@article{arxiv.1509.08275,
  title  = {Betti posets and the Stanley depth},
  author = {Lukas Katthän},
  journal= {arXiv preprint arXiv:1509.08275},
  year   = {2016}
}

Comments

10 pages. Clarified the proof of 3.6. To appear in the Arnold Mathematical Journal

R2 v1 2026-06-22T11:06:55.324Z