English

Berezin number inequalities for Hilbert space operators

Functional Analysis 2018-05-08 v2

Abstract

In this paper, by using of the definition Berezin symbol, we show some Berezin number inequalities. Among other inequalities, it is shown that if A,B,XB(H)A, B, X\in{\mathbb{B}}(\mathscr H), then ber(AX±XA)ber12(AA+AA)ber12(XX+XX)\mathbf{ber}(AX\pm XA)\leqslant \mathbf{ber}^{\frac{1}{2}}\left(A^*A+AA^*\right)\mathbf{ber}^{\frac{1}{2}}\left(X^*X+XX^*\right) and ber2(AXB)X2ber(AA)ber(BB).\mathbf{ber}^2(A^*XB)\leqslant\|X\|^2\mathbf{ber}(A^*A)\mathbf{ber}(B^*B).

Cite

@article{arxiv.1805.01018,
  title  = {Berezin number inequalities for Hilbert space operators},
  author = {Mojtaba Bakherad and Mubariz T. Karaev},
  journal= {arXiv preprint arXiv:1805.01018},
  year   = {2018}
}
R2 v1 2026-06-23T01:43:21.510Z