English

Average Local Independence and the Spanning-Tree Leaf Number: A Proof of Graffiti.pc Conjecture 2

Combinatorics 2026-07-27 v1

Abstract

We prove Graffiti.pc Conjecture 2, a 1996 conjecture listed as open on the \emph{Written on the Wall II} page marked ``Last update 7/23/26.'' Let GG be a finite simple connected graph. For vV(G)v\in V(G), let I(v)=α(G[NG(v)])I(v)=\alpha(G[N_G(v)]), and let Iavg(G)I_{\mathrm{avg}}(G) be the average of these local independence numbers. The conjecture states that the maximum number Ls(G)L_s(G) of leaves in a spanning tree of GG satisfies Ls(G)2(Iavg(G)1)L_s(G)\ge 2\bigl(I_{\mathrm{avg}}(G)-1\bigr). We establish this inequality by extracting a triangle-free spanning subgraph that retains at least half of the total local-independence mass. A degree-square argument then produces a double star with sufficiently many leaves, and this tree extends to a spanning tree without losing leaves. Balanced complete bipartite graphs show that the bound is sharp.

Keywords

Cite

@article{arxiv.2607.24020,
  title  = {Average Local Independence and the Spanning-Tree Leaf Number: A Proof of Graffiti.pc Conjecture 2},
  author = {Yanmohan Wang and Tianyue Dai and Rui Tong},
  journal= {arXiv preprint arXiv:2607.24020},
  year   = {2026}
}

Comments

5 pages, no figures; self-contained proof