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Another determinantal inequality involving partial traces

Functional Analysis 2020-02-25 v1

Abstract

Let AA be a positive semidefinite m×mm\times m block matrix with each block nn-square, then the following determinantal inequality for partial traces holds (trA)mndet(tr2A)ndetAdet(tr1A)m, (\mathrm{tr} A)^{mn} - \det(\mathrm{tr}_2 A)^n \ge \bigl| \det A - \det(\mathrm{tr}_1 A)^m \bigr|, where tr1\mathrm{tr}_1 and tr2\mathrm{tr}_2 stand for the first and second partial trace, respectively. This result improves a recent result of Lin [14].

Keywords

Cite

@article{arxiv.2002.09652,
  title  = {Another determinantal inequality involving partial traces},
  author = {Yongtao Li and Lihua Feng and Weijun Liu and Yang Huang},
  journal= {arXiv preprint arXiv:2002.09652},
  year   = {2020}
}

Comments

8 pages

R2 v1 2026-06-23T13:50:13.045Z