English

An elementary proof that random Fibonacci sequences grow exponentially

Number Theory 2007-05-23 v2

Abstract

We consider random Fibonacci sequences given by xn+1=±βxn+xn1x_{n+1}=\pm \beta x_{n}+x_{n-1}. Viswanath (\cite{viswanath}), following Furstenberg (\cite{furst}) showed that when β=1\beta = 1, limnxn1/n=1.13...\lim_{n\to \infty}|x_{n}|^{1/n}=1.13..., but his proof involves the use of floating point computer calculations. We give a completely elementary proof that 1.25577(E(xn))1/n1.120951.25577 \ge (E(|x_{n}|))^{1/n} \ge 1.12095 where E(xn)E(|x_{n}|) is the expected value for the absolute value of the nnth term in a random Fibonacci sequence. We compute this expected value using recurrence relations which bound the sum of all possible nnth terms for such sequences. In addition, we give upper an lower

Keywords

Cite

@article{arxiv.math/0510159,
  title  = {An elementary proof that random Fibonacci sequences grow exponentially},
  author = {Eran Makover and Jeffrey McGowan},
  journal= {arXiv preprint arXiv:math/0510159},
  year   = {2007}
}

Comments

7 pages, 2 figures