English

An Algebraic Approach to the Goldbach and Polignac Conjectures Using Mihailescu's Theorem and $p$-adic Analysis

General Mathematics 2026-02-17 v13

Abstract

We prove the Goldbach Conjecture using p-adic analysis and algebraic methods, requiring no knowledge of prime gaps or distribution by showing counterexamples exist if and only if certain polynomials have integer solutions. Assuming, for the sake of contradiction, a counter-example 2a2a exists, and labeling the set of primes up to aa as P\mathcal{P}, we construct the Goldbach Polynomial G(z):=pkP(zpk)pkPpkαk \mathcal{G}_-(z) := \prod_{p_k \in \mathcal{P}} (z - p_k) - \prod_{p_k \in \mathcal{P}}p_k^{\alpha_k} with conditions G(2a)=0\mathcal{G}_-(2a) = 0 and all αk\alpha_k are unique natural numbers. Using Hensel's Lemma, we prove each 2apk2a - p_k must be a perfect prime power of only a prime in P\mathcal{P}, giving solutions of the form 2a=pjαj+pk2a = p_j^{\alpha_j} + p_k. Applying Mih\u{a}ilescu's Theorem (Catalan's Conjecture) shows the largest such polynomial is G(z)=(z2)(z3)22×3:G(6)=0 \mathcal{G}_-(z) = (z - 2)(z - 3) - 2^2 \times 3 : \mathcal{G}_-(6) = 0 proving no counterexamples exist for a>3a > 3. We then prove the Goldbach Difference Conjecture similarly, from which the Polignac Conjecture follows.

Keywords

Cite

@article{arxiv.2206.01179,
  title  = {An Algebraic Approach to the Goldbach and Polignac Conjectures Using Mihailescu's Theorem and $p$-adic Analysis},
  author = {Jason R. South},
  journal= {arXiv preprint arXiv:2206.01179},
  year   = {2026}
}

Comments

19 pages, typos were fixed from the last version and significant simplifications made