A note on inverting the dijoin of oriented graphs

For an oriented graph $D$ and a set $X\subseteq V(D)$, the inversion of $X$ in $D$ is the graph obtained from $D$ by reversing the orientation of each edge that has both endpoints in $X$. Define the inversion number of $D$, denoted $\mathrm{inv}(D)$, to be the minimum number of inversions required to obtain an acyclic oriented graph from $D$. The dijoin, denoted $D_1\rightarrow D_2$, of two oriented graphs $D_1$ and $D_2$ is constructed by taking vertex-disjoint copies of $D_1$ and $D_2$ and adding all edges from $D_1$ to $D_2$. We show that $\mathrm{inv}({D_1 \rightarrow D_2}) > \mathrm{inv}(D_1)$, for any oriented graphs $D_1$ and $D_2$ such that $\mathrm{inv}(D_1) = \mathrm{inv}(D_2) \ge 1$. This resolves a question of Aubian, Havet, H\"orsch, Klingelhoefer, Nisse, Rambaud and Vermande. Our proof proceeds via a natural connection between the graph inversion number and the subgraph complementation number.