English

A counterexample to Borsuk's conjecture

Metric Geometry 2008-02-03 v1 Combinatorics

Abstract

Let f(d)f(d) be the smallest number so that every set in RdR^d of diameter 1 can be partitioned into f(d)f(d) sets of diameter smaller than 1. Borsuk's conjecture was that f(d) ⁣= ⁣d ⁣+ ⁣1f(d)\! =\!d\!+\!1. We prove that f(d) ⁣ ⁣(1.2)df(d)\! \ge\! (1.2)^{\sqrt d} for large~dd.

Cite

@article{arxiv.math/9307229,
  title  = {A counterexample to Borsuk's conjecture},
  author = {Jeff Kahn and Gil Kalai},
  journal= {arXiv preprint arXiv:math/9307229},
  year   = {2008}
}

Comments

3 pages